1. D 11. E 21. B 2. B 12. B 22. A 3. C 13. C 23. E 4. D 14. E 24. A 5. A 15. E 25. A 6. D 16. C 26. C 7. B 17. A 27. C 8. E 18. B 28. D 9. A 19. E 29. B 10.D 20. C 30. D 31.a. VHor = Vcosq VHor = 24.0cos60o VHor = 12m/s Note: the horizontal component of velocity is constant between P and X. b. SHor = VHort SHor = 12x26 SHor = 312m 32. Fres = (9x104-4x104)3 Fres = 5x104x3 Fres = 15x104N (to the left) 33.a. RP/RQ = RR/RS When this is true the reading on the voltmeter is 0V. b. The p.d. across the battery does not affect the above ratio of the resistors. The bridge is therefore still balanced, and the voltmeter reading will not change from 0V. 34.a. VRMS = Vpeak/SQRT2 VRMS = 10/1.414 VRMS = 7.07V b. f = 1/T T = 8x0.2ms = 1.6ms T = 1.6x10-3 f = 1/1.6x10-3 f = 625Hz 35.a. The pupil assumes that there is 100% efficiency in the process converting the energy stored in the capacitor into heat energy. There is also the assumption that all the heat energy is absorbed by the oil. b. The energy stored in the capacitor can be calculated using: E = CV2/2 E = 5x10-6x102/2 E = 2.5x10-4J This amount of energy would not produce a measurable change in the temperature of the oil. 36. For the first minimum: Path difference = 1/2l AB-AP = 1/2l 43-41 = 1/2l 2 = 1/2l l = 4cm 37.a. Alpha radiation. b. The fact that most of the radiation passes straight through indicates that most of the atom must be empty space. However, the fact that some "bounces back" provides evidence that the alpha particle occasionally collides with a massive body. It is therefore reasonable to conclude that atoms are mainly empty space with a large mass concentrated at the centre.
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